-x^2+100x-2500=0

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Solution for -x^2+100x-2500=0 equation: 



-x^2+100x-2500=0

We add all the numbers together, and all the variables

-1x^2+100x-2500=0

a = -1; b = 100; c = -2500;
Δ = b2-4ac
Δ = 1002-4·(-1)·(-2500)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-100}{-2}=+50$

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